Triangle Area Equation

Introduction to triangle area equation:
In this article we discuss about the triangle area equation. The triangle can be defined as three closed sided polygon. To find the area of triangle is multiplying by the height and base, and then dividing by two. Basically the triangle comes from parallelogram. The parallelograms can be divided into two triangles. The each triangle area is equal to the one-half the area of the parallelogram. The parallelogram and triangle figure is given below,

Triangle Area Equation:

The area of parallelogram equation is given below,

`Area=Base xx Height`

That is, `A=B xx H`

The area of the triangle equation is given below,

Area of triangle=`"parallelogram"/2` or

Area= `(Base xx Height)/2` or

Area= `1/2 xx (B xx H)`

Where

B is the base of the triangle

H is the height of the triangle

We know the length of all sides of the triangle; we can calculate the area by using the Heron’s equation. Please express your views of this topic how to find the volume of a triangular prism by commenting on blog.

In this case first we have to define a perimeter of a triangle.

Perimeter= (a side + b side + c side)

Semi-Perimeter= `(a side + b side + c side)/2`

Therefore the heron’s equation is given below,

Area=`sqrt(s.(s-a).(s-b).(s-c))`

The all sides of the triangle figure is given below,

Example Problems for Triangle Area Equation:
Triangle area equation problem 1:

To find the area of a triangle with base 40 inches and height 6 inches?

Solution:

Given data: base (B) =40 inches and height (H) =6 inches.

Area of a triangle=`1/2` `xx` (B `xx` H)

=`1/2` `xx` (40 `xx` 6)

=`1/2 xx` 240

`Area = 120 i n^2`

Therefore the area of the triangle value is `120 i n^2` .

Triangle area equation problem 2:

A triangle has side a =10 in, side b =14 in and side c =12 in. Find its area?

Solution:

Given data: side a=10 in, side b=14 in, side c=12 in

First we find the perimeter of the triangle.

The perimeter = 10+ 14 + 12 = 36.

Next we find the semi-perimeter of the triangle.

The semi-perimeter is one half of this or 18

Using Heron's formula,

area = `sqrt (s . (s-10). (s-14) .(s-12))`

= `sqrt (18 . (18-10) .(18-14) . (18-12))`

= `sqrt (18 .(8) . (4) . (6))`

= `sqrt (3456)`

=  `58.78 i n^2`