Double Counting Online Study

Introduction to double counting online study:

In mathematics the double counting is the counting in two ways is a proof technique that involves counting the size of the set. Double counting is the simple method. Tutor is a person, they are number of the tutors available for online. Online is defined as connecting person through the internet. There are number of the website available in online. In this article we see in detail about double counting online study.

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Example 1: double counting tutoring:


What is the probability of the select ace and queen from punch of card.

Solution:

The probability for ace is occurs `4/52` .

The probability for queen is occurs `4/52`

The combination occurrences of common probability is `1/52`

P (A+B) = P (A) +P (B)-P (AB)

=`4/52+4/52-1/52`

=`8/52-1/52`

=`7/52`

=0.135


Example 2: double counting online study:


A bag contains 6 yellow balls and 6 blue, what is probability for drawn yellow ball, balck ball?

Solution:

Total number of the ball = 12

Yellow ball =5

Blue ball = 15

The probability for yellow ball = `15/30`

The probability for blue ball = `15/30`

P (A + B) = P (A) + P (B) - P (AB)

= `15/30 + 15/30 - 1/30`

= `30/30-1/30`

= 0.97


Example 3: double counting online study:


A bag contains 15 orange ball and 5 green ball, what is the probability for draw orange and green ball.

Solution:

Total number of ball = 20

Number of the orange ball is 15

Number of the blue ball is the 5

Probability of green ball is = `15/20` = 0.75

Probability of blue ball is = `5/20` = 0.25

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Example 4: double counting online study:


What is the probability for selecting either ace otherwise a queen from punch of card.

Solution:

The probability for ace is occurs `4/52.`

The probability for queen is occurs `4/52`

The combination occurrences of common probability is `1/52`

P (A+B) = P (A) +P (B)-P (AB)

=`4/52+4/52-1/52`

=`8/52-1/52`

=`7/52`

=0.13

Math Subtraction Problems Online Study

Introduction to Math Subtraction Problems Online Study:

Many online websites are available today. In those websites, subtracting a number from another number can be explained step by step briefly about the topic for lower grade students to understand clearly. The subtraction is said to be removing a part from the whole. The act of taking one number away from another is known as subtraction in math. For example, subtracting 4 – 2 is 2. Let us see about math subtraction problems online study in this article.Please express your views of this topic 3 digit subtraction with regrouping by commenting on blog.


Worked Examples to Math Subtraction Problems Online Study

Let us learn some of the solved examples explained through online about subtraction in math.

Problem 1:

Solve subtraction of two numbers 63 – (-12).

Solution:

Step 1:

Here, the number 63 is minuend and the number 12 is subtrahend.

Let us write the given number one under the other like,

63 (minuend)

12 (subtrahend)

------------------------

Here, the subtrahend is minus 12 so minus into minus is equal to plus.

Add those numbers and put the sign of larger number to the result.

Step 2:

Add the one’s place and this carry can be added to the tens place.

3 + 2 = 5

Step 3:

Add the tens place,

6 + 1 = 7

Step 4:

Regroup the numbers, we get,

7 + 5 = 75

The larger number is + 63. So, the sign of the result is also + 75.

Therefore, the solution for adding 63 – (-12) is 75.

Problem 2:

Solve subtraction of two numbers – 34 – 45.

Solution:

Step 1:

Here, the number 24 is minuend and the number 45 is subtrahend.

Let us write the given number one under the other like,

24 (minuend)

45 (subtrahend)

---------------------------

Add those numbers and put negative sign before the result.

Step 2:

Add the one’s place,  we get,

4 + 5 = 9

Step 3:

Add the tens place with carry of one’s place,

2 + 4 = 6

Step 4:

Regroup the numbers, we get,

6 + 9 = 69

Therefore, the solution for subtracting – 24 – 45 is 69.


Another Problem to Math Subtraction Problems Online Study


Problem 3:

Solve subtraction of two numbers 23 – 8.

Solution:

Step 1:

Here, the number 23 is minuend and the number 8 is subtrahend.

Let us write the given number one under the other like,

23 (minuend)

08 (subtrahend)

---------------------------

Subtract the two numbers and place the sign of larger number before the answer.

Step 2:

Subtract the one’s place,  we get,

3 – 8 = we cannot subtract 8 from 3. So, we borrow 1 from the minuend tens place 2. So the one's place becomes 13 – 8 = 5 and the tens place of minuend becomes 2 – 1 = 1.

Step 3:

Subtract the tens place, we get,

1 – 0 = 1 (There is no tens place column in the subtrahend place)

Step 4:

Regroup the numbers, we get,

1 + 5 = 15

Therefore, the solution for subtracting 23 – 8 is 15.

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Practice Problems to Math Subtraction Problems Online Study


1. Subtraction of two numbers  – 42 – 12.

Key: - 54

2. Subtraction of two numbers – 23 – (- 13).

Key: - 10

3. Subtraction of two numbers 18 – (- 2).

Key: 20

4. Subtraction of two numbers 43 – 37.

Key: 6

5. Subtraction of two numbers - 26 + 31.

Key: 5

How to Study Successfully

Introduction to how to study successfully:
How to study successfully in math is to learn the  basic formulas and method of solving that math problems, then see the solved problems of that similar type. Now we get an idea of how to solve that math problem then try how to solve that problem step by step. how to study successfully is about a general math, so let us take problems from algebra. In this article let us see problems to how to study successfully.


How to study successfully:

Example 1:

Find the value of the expression 4x + 7 , if x = 7

Solution:

use x = 7 in the given expression 4x + 7

4x+ 7 = 4(7) + 7

= 28 + 7

X  = 35

Here the value of the expression is 35.

Example 2:

If four times of a number is equal to 16. Then find what exactly the number is?

Solution:

let us assume the unknown number as " X "

Given   4 * X = 16.

Move leftside term to right

Then          X = `16/4`

The unknown number x is

X = 4

Example 3:

Find the Coefficients combined in the given equation:

24x2 + 7y + 5xy + 12

Solution:

Here Coefficient of x2 is 24

Coefficient of y is 7

Coefficient of xy is 5

Example 4:

Evaluate 22 - (-3) × 4   + (-6) / 3

Solution :

= 22 - (-3) × 4 + (-6) / 3

= 22 - (-12) + (-2)

= 22 + 12 - 2

= 22 + 10

= 32


How to study successfully:


Example 5:

Find the value of the expression 25x+8 , if x= 3

Solution:

Substitute x = 3 in the given expression 25x+8

25+8 = 25(3)+8

= 75 + 8

X  = 83

Here the value of the expression is 83.

Example 6:

Solve: 8x - 2 = 118

Solution:

Given, 8x - 2 = 118

8x = 118 + 2

8x = 120

x = `120/8`

or    x = 15

Example 7:

Solve the following system:

x + y = 14 - (1)

4x - y = 11 - (2)

Solution:

Solve the (1) equation

y =14 -x

substitute in (2)equation

4x - (14 - x)=11

4x - 14 + x=11

5x=25

x=5

substitute value of x in (1)equation

5 + y=14

y=9

The solution is, (5, 9).

Self Study Math

Introduction:

Let us learn the math by self. Its not a difficult one to study the math by self, we have to concentrate on the problems and show some interest. First of all, we should not think that math is difficult one.

Pre-algebra students with weak arithmetic skills need special instruction.

Repeating students need something new to hold their interest.

Students need Math Study Skills.

Students with disabilities benefit from multi-modality instruction.

Ten Steps to Doing Self Study Math Homework

Review related textbook material.

Review appropriate lecture notes.

Do homework neatly.

Write down every problem step.

Understand reasons for problem steps.

For difficult problems repeat 1 -5 and review similar problems, call another student, use other references, see a tutor or teacher.

Finish by working a problem successfully.

Recall or write down important concepts.

Make up note cards for difficult concepts.

Don’t get behind.


Ten Steps to Doing Online self study math Homework


Review related textbook material.

Review appropriate lecture notes.

Do homework neatly.

Must write down problem and every problem step.

Understand reasons for problem steps instead of using the click and go method.

For difficult problems use the resources provided by the software (videos /tutor line).

Finish by working a problem successfully.

Recall or write down important concepts.

Develop virtual note cards  by using www.studystack.com.

Don’t get behind – you could get block out.

Taking the Test

Ten Steps for Taking a self study math Test :

Memory Data Dump

Preview Test

2nd Memory Data Dump

Test Progress Schedule

Answer Easy Questions

Skip Difficult Questions

Review Skipped Questions

Guess at Remaining Questions

Review All of the Test

Use all the Test Time


Six Types of Test-taking self study math Errors


Misread Directions

Careless Errors

Concept Errors

Application Errors

Test Procedure Errors

Study Errors

Example for self study math:

A coin is tossed 60 times. 25 times tail appears. Find the experimental probability of getting tail.

Solution:

Step 1:

Probability = `("Number of times the event happen") / ("Total number of trials")` .

Step 2:

Number of times tail appeared = 25.

Step 3:

Total number of experiments = 60.

Step 4:

Therefore experimental probability of getting a tail = 25/60= 5/12

Experimental Research Study

Introduction to experimental research study:
A probability experimental is a stipulation where probability affects the outcome. A coin flip is a probability experiment because chance affect whether a coin will ground heads or tails when it is flipped. In probability, an experiment is a procedure with an outcome that deepens leading chance. In this article we are learning about the experiment research study. The experimental research study is a collection research processes. It us used to manipulation and controlled to understand the casual process.


Example 1 –Experimental Research Study:

Now we are going to solve the probability problem for experimental research study.

The three coins are flipped at a time.

What is the probability of get accurately three tails or two heads with one tail?

Solution:

The sample space, when three coins tossed is,

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

n(S) = 8

A be the event of getting three tails,

n (A) = {TTT} = 3

B be the event of getting two heads with one tail,

n (B) = {HHT, HTH, THH} = 3

P (A) = `3/8`

P (B) = `3/8`

P (A or B) = P (A) + P (B)

= `3/8 ` + `3/8`

= `6/8`

= 0.75

Here the expected value is 0.75

Understanding Probability in Math is always challenging for me but thanks to all math help websites to help me out.

Example 2 –Experimental Research Study:


Let see we will sample probability problem for experimental research study.

From the following scores

15.6, 13.5, 20.3, 12.4, 14.9, 8.2, 7.6.

1. above 13.6values

2. below 13.6 values

Probability for finding above 13.6 values:

The given values are 15.6, 13.5, 20.3, 12.4, 14.9, 8.2, 7.6.

Above 13.6 scores = 15.6, 20.3, 14.9.

In the given scores the above 13.6 scores probability values are (15.6, 20.3, 14.9).

Probability for above 13.6 scores =3

Total scores = 7

Probability =`("Above 13.6 values")/("Total given values")`

Total scores = 7

Probability for above 13.6 scores =`3/7`

Answer:

`3/7`

Find the probability for below 13.6 scores:

Solution:

The given scores are,

15.6, 13.5, 20.3, 12.4, 14.9, 8.2, 7.6.

Below 13.6 scores are 13.5, 12.4, 8.2, 7.6.

Formulas for getting probabilities for below 15.1 scores are

Probability =`("Below13.6 values")/("Total given values")`

Here below 13.6 scores values = 4.

Total given scores = 7.

So the probability for below 13.6 scores = `4/7`

= `4/7.`

Answer:

`4/7`

These are experimental research study.

That’s all about experimental research study.

Work Study Homework Ideas

Introduction to work study homework ideas:
The word study homework ideas represent the ideas for the student's homework. Homework is the process of doing some problems of work at home that are not done in the classes.When the students did not practice on the particular exercise or they have inability to do their homework or otherwise if the teacher have no time to do all the problems in the whole, then the teacher in the class need to check their children's homework.

(source from Wikipedia)

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Some examples to explain word study homework ideas:


Let us see some of the word study homework problems.

Solve for the equation 4i + 30= 3i +17

Solution:

4i + 30 - 3i = 3i + 17 - 3i

i + 30 = 17

i + 30 - 30 = 17 - 30

i= -13

In this problem the variable 'i' exist. When the process is ongoing we have the small doubt that either it is the variable or the representation of imaginary number in complex numbers. In execution of the problems we clearly known that it is variable. For practice the teachers give homework to the students with the ideas to study.


Some more problems to explain "word study homework ideas":

Find the mode of the given set of numbers: 11, 11, 12, 14, 13, 12, 11, 12, 12, 14

Solution:

Consider the given numbers we have to arrange that, after arranging we get
11,11, 11, 12,12, 12, 12, 13, 14, 14
Mode for this data is 12 because 12 occurs more frequently than other observations.

In this problem we have different numbers on processing  we have doubt about in what way the prosecution begins in the way of mode, mean. We shortly confused  due to their different operations on same name (slightly moderating their pronunciation).

consider  the margins of victory in the football matches of a league that are following
1, 3, 2, 5, 1, 4, 6, 2, 5, 2, 2, 2, 4, 1, 2, 3, 1, 1, 2, 3, 2, 6, 4, 3, 2, 1, 1, 4, 2, 1, 5, 3, 3, 2, 3, 2, 4, 2, 1, 2
Find the mode for this data.

Solution:

2 has occurred the highest number of times therefore the mode is ' 2'.

Practice problem for the word study homework ideas

consider the following statements we have to tell whether the statement is true or false:
(i) The mode is always one of the numbers in a data.
(ii) The mean can be one of the numbers in a data.
(iii) The median is always one of the numbers in a data.
(iv) A data always has a mode.
(v) The data 6, 4, 3, 8, 9, 12, 13, 9 has mean 9.