Showing posts with label the probability. Show all posts
Showing posts with label the probability. Show all posts

Wednesday, May 29, 2013

Double Counting Online Study


Introduction to double counting online study:

In mathematics the double counting is the counting in two ways is a proof technique that involves counting the size of the set. Double counting is the simple method. Tutor is a person, they are number of the tutors available for online. Online is defined as connecting person through the internet. There are number of the website available in online. In this article we see in detail about double counting online study.

Having problem with Law of Total Probability keep reading my upcoming posts, i will try to help you.

Example 1: double counting tutoring:


What is the probability of the select ace and queen from punch of card.

Solution:

The probability for ace is occurs `4/52` .

The probability for queen is occurs `4/52`

The combination occurrences of common probability is `1/52`

P (A+B) = P (A) +P (B)-P (AB)

=`4/52+4/52-1/52`

=`8/52-1/52`

=`7/52`

=0.135


Example 2: double counting online study:


A bag contains 6 yellow balls and 6 blue, what is probability for drawn yellow ball, balck ball?

Solution:

Total number of the ball = 12

Yellow ball =5

Blue ball = 15

The probability for yellow ball = `15/30`

The probability for blue ball = `15/30`

P (A + B) = P (A) + P (B) - P (AB)

= `15/30 + 15/30 - 1/30`

= `30/30-1/30`

= 0.97


Example 3: double counting online study:


A bag contains 15 orange ball and 5 green ball, what is the probability for draw orange and green ball.

Solution:

Total number of ball = 20

Number of the orange ball is 15

Number of the blue ball is the 5

Probability of green ball is = `15/20` = 0.75

Probability of blue ball is = `5/20` = 0.25

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Example 4: double counting online study:


What is the probability for selecting either ace otherwise a queen from punch of card.

Solution:

The probability for ace is occurs `4/52.`

The probability for queen is occurs `4/52`

The combination occurrences of common probability is `1/52`

P (A+B) = P (A) +P (B)-P (AB)

=`4/52+4/52-1/52`

=`8/52-1/52`

=`7/52`

=0.13