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We need to talk about logarithms. Say you have 2^x = 64
(2^x is my way of saying "2 raised to the x power"), and you want to
solve for x.
Well, we know that
64 = 2*32 = 2*(2*16) = 2*2*2*8 = 2*2*2*2*2*2 = 2^6, so x = 6.
How about 2^x = 5? There we're stuck, because 2^2 = 4 and 2^3 = 8
so x should be somewhere between 2 and 3 to make 2^x = 5.
There's another way of saying what x should be, and this is called the
logarithm of 5 to the base 2. examples on free math; That is, x = log[2](5); (the 2 should be
a subscript, like a power but typed a bit below the log, so it isn't
log 10). In general, the solution to b^x = n for some given b and n is
x = log[b](n). b is called the *base* of the logarithm.
Learn more on online math tutors.
We need to talk about logarithms. Say you have 2^x = 64
(2^x is my way of saying "2 raised to the x power"), and you want to
solve for x.
Well, we know that
64 = 2*32 = 2*(2*16) = 2*2*2*8 = 2*2*2*2*2*2 = 2^6, so x = 6.
How about 2^x = 5? There we're stuck, because 2^2 = 4 and 2^3 = 8
so x should be somewhere between 2 and 3 to make 2^x = 5.
There's another way of saying what x should be, and this is called the
logarithm of 5 to the base 2. examples on free math; That is, x = log[2](5); (the 2 should be
a subscript, like a power but typed a bit below the log, so it isn't
log 10). In general, the solution to b^x = n for some given b and n is
x = log[b](n). b is called the *base* of the logarithm.
Learn more on online math tutors.




