Study About Geometric Problems

Introduction to study about geometric problems:

Geometry (Ancient Greek: γεωμετρία; geo- "earth", -metria "measurement") "Earth-measuring" is a part of mathematics concerned with questions of size, shape, relative position of figures, and the properties of space. Geometry is one of the oldest sciences. Initially a body of practical knowledge concerning lengths, areas, and volumes, in the 3rd century BC geometry was put into an axiomatic form by Euclid, whose treatment—Euclidean geometry—set a standard for many centuries to follow.


Formulas on study about geometric problems:


To study about the formulas of geometric which are givenas below:

Rectangle formulas:

Rectangle Perimeter = l + l + w + w = 2 × l + 2 × w = 2+2w

Area of the Rectangle = l × w

Square formulas:

Perimeter of the square = c + c + c + c = 4 × c = 4c

Area of the square = c* c = c 2

Parallelogram formulas:

Perimeter of the Parallelogram= c + c + d + d = 2 × c + 2 × d = 2c + 2d

Area of the Parallelogram = b × h

Rhombus formulas:

Perimeter of the Rhombus = c + c + c + c = 4 × c = 4c

Area of the Rhombus = b × h

Triangle formulas:

Perimeter of the Triangle = c + d + e

Area of the Triangle = (b × h)/2

Trapezoid formulas:

Perimeter of the Trapezoid = c +d + e + f
Area of the Trapezoid = (c+d) * h / 2

Circle formulas:

Perimeter of Circle = 2 × pi × R or Perimeter = pi × d

Area of the Circle = pi × R 2 or Area = (pi × d2)/4


Problems on study about geometric problems:


Study geometric Square problem:

Problem 1:

Calculate the area and perimeter of square when side length is 8cm?

Solution:

Area of square = (side*side)

=8*8

=>64cm2

Perimeter of square= 4* side

=4*8

= 32cm

Study geometric Rectangle problem:

Problem 2:

Find the area and perimeter of rectangle with length 9cm,width 7 cm?

Solution:

Area of rectangle = Length x width

= 9*7

= 63cm2

Perimeter of rectangle=2(Length +width)

=2(9+7)

= 32cm

Study geometric Triangle problem:

Problem 3:

Find the area and perimeter of triangle Base=8, Height=9, other two sides are 10,11?

Solution:

Area=1/2/(8*9)

=72/2

= 36cm2

Perimeter= (sum of three sides)

= (8+10+11)

= 29 cm