Introduction to study about geometric problems:
Geometry (Ancient Greek: γεωμετρία; geo- "earth", -metria "measurement") "Earth-measuring" is a part of mathematics concerned with questions of size, shape, relative position of figures, and the properties of space. Geometry is one of the oldest sciences. Initially a body of practical knowledge concerning lengths, areas, and volumes, in the 3rd century BC geometry was put into an axiomatic form by Euclid, whose treatment—Euclidean geometry—set a standard for many centuries to follow.
Formulas on study about geometric problems:
To study about the formulas of geometric which are givenas below:
Rectangle formulas:
Rectangle Perimeter = l + l + w + w = 2 × l + 2 × w = 2+2w
Area of the Rectangle = l × w
Square formulas:
Perimeter of the square = c + c + c + c = 4 × c = 4c
Area of the square = c* c = c 2
Parallelogram formulas:
Perimeter of the Parallelogram= c + c + d + d = 2 × c + 2 × d = 2c + 2d
Area of the Parallelogram = b × h
Rhombus formulas:
Perimeter of the Rhombus = c + c + c + c = 4 × c = 4c
Area of the Rhombus = b × h
Triangle formulas:
Perimeter of the Triangle = c + d + e
Area of the Triangle = (b × h)/2
Trapezoid formulas:
Perimeter of the Trapezoid = c +d + e + f
Area of the Trapezoid = (c+d) * h / 2
Circle formulas:
Perimeter of Circle = 2 × pi × R or Perimeter = pi × d
Area of the Circle = pi × R 2 or Area = (pi × d2)/4
Problems on study about geometric problems:
Study geometric Square problem:
Problem 1:
Calculate the area and perimeter of square when side length is 8cm?
Solution:
Area of square = (side*side)
=8*8
=>64cm2
Perimeter of square= 4* side
=4*8
= 32cm
Study geometric Rectangle problem:
Problem 2:
Find the area and perimeter of rectangle with length 9cm,width 7 cm?
Solution:
Area of rectangle = Length x width
= 9*7
= 63cm2
Perimeter of rectangle=2(Length +width)
=2(9+7)
= 32cm
Study geometric Triangle problem:
Problem 3:
Find the area and perimeter of triangle Base=8, Height=9, other two sides are 10,11?
Solution:
Area=1/2/(8*9)
=72/2
= 36cm2
Perimeter= (sum of three sides)
= (8+10+11)
= 29 cm
Geometry (Ancient Greek: γεωμετρία; geo- "earth", -metria "measurement") "Earth-measuring" is a part of mathematics concerned with questions of size, shape, relative position of figures, and the properties of space. Geometry is one of the oldest sciences. Initially a body of practical knowledge concerning lengths, areas, and volumes, in the 3rd century BC geometry was put into an axiomatic form by Euclid, whose treatment—Euclidean geometry—set a standard for many centuries to follow.
Formulas on study about geometric problems:
To study about the formulas of geometric which are givenas below:
Rectangle formulas:
Rectangle Perimeter = l + l + w + w = 2 × l + 2 × w = 2+2w
Area of the Rectangle = l × w
Square formulas:
Perimeter of the square = c + c + c + c = 4 × c = 4c
Area of the square = c* c = c 2
Parallelogram formulas:
Perimeter of the Parallelogram= c + c + d + d = 2 × c + 2 × d = 2c + 2d
Area of the Parallelogram = b × h
Rhombus formulas:
Perimeter of the Rhombus = c + c + c + c = 4 × c = 4c
Area of the Rhombus = b × h
Triangle formulas:
Perimeter of the Triangle = c + d + e
Area of the Triangle = (b × h)/2
Trapezoid formulas:
Perimeter of the Trapezoid = c +d + e + f
Area of the Trapezoid = (c+d) * h / 2
Circle formulas:
Perimeter of Circle = 2 × pi × R or Perimeter = pi × d
Area of the Circle = pi × R 2 or Area = (pi × d2)/4
Problems on study about geometric problems:
Study geometric Square problem:
Problem 1:
Calculate the area and perimeter of square when side length is 8cm?
Solution:
Area of square = (side*side)
=8*8
=>64cm2
Perimeter of square= 4* side
=4*8
= 32cm
Study geometric Rectangle problem:
Problem 2:
Find the area and perimeter of rectangle with length 9cm,width 7 cm?
Solution:
Area of rectangle = Length x width
= 9*7
= 63cm2
Perimeter of rectangle=2(Length +width)
=2(9+7)
= 32cm
Study geometric Triangle problem:
Problem 3:
Find the area and perimeter of triangle Base=8, Height=9, other two sides are 10,11?
Solution:
Area=1/2/(8*9)
=72/2
= 36cm2
Perimeter= (sum of three sides)
= (8+10+11)
= 29 cm
